Rate Analysis For Mortar

Consider Mix Ratio 1: 6 and volume of mortar is 1 cubic meter

Dry volume of mortar = wet volume x 1.33

Dry Volume = 1 m³ x 1.33 = 1.33 m³

Quantity of cement = {(Dry volume of mortar x cement ratio) / (Sum of ratio)}

Quantity of cement = (1.33 x 1) /(1+6) = 0.19 m³

Density of cement = 1440 kg / m³

So, Weight of cement = 1440 x 0.19 = 273.6Kg

1 bag of cement = 50 kg

So,Number of cement bags = 273.6 kg / 50 = 5.47 No.’s

As we know , Cement: Sand = 1: 6

Thus,

Quantity of sand = volume of cement x 6

Quantity of sand = 0.19 m³ x 6 = 1.14 m³

1 m³ = 35.3147 cubic feet (CFT)

Quantity of sand = 1.14 x 35.3147 = 40.258 CFT

Density of dry sand = 1600 kg / m³

Weight of sand = 1.14 m³ x 1600 kg / m³ = 1824 kg = 1.824 tonnes

For easy calculation let me show you rate analysis of mortar in the table below:

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